Proof
Complete each triangle to a parallelogram via I.31, then apply I.34
and I.35.
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Depends on (3)
- I.31Proposition I.31Through a given point to draw a straight line parallel to a given straight line.
- I.34Proposition I.34In parallelogrammic areas the opposite sides and angles are equal to one another, and the diameter bisects the areas.
- I.35Proposition I.35Parallelograms which are on the same base and in the same parallels are equal to one another.
Required by (dependents) (3)
- I.39Proposition I.39Equal triangles which are on the same base and on the same side are also in the same parallels.
- I.41Proposition I.41If a parallelogram have the same base with a triangle and be in the same parallels, the parallelogram is double of the…
- VI.2Proposition VI.2If a straight line be drawn parallel to one of the sides of a triangle, it will cut the sides of the triangle…
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