Proposition·Untested·2605.00009

Proposition II.10

If a straight line be bisected and a straight line be added to it in a straight line, the square on the whole with the added straight line and the square on the added straight line both together are double of the square on the half and of the square described on the straight line made up of the half and the added straight line as on one straight line.

Proof

Let be bisected at (I.10) and produced to . At erect at right angles to (I.11), with . Join , , . Through draw parallel to , of length such that meets the line through parallel to at (I.31). As in II.9, is a right angle (right-isoceles triangles and ). Triangle is also right-angled, with the right angle at in the configuration where lies on the extension of . Apply I.47 twice (to and to the triangle formed by extending the constructions to ): \[ AD^2 + DB^2 \;=\; 2\cdot AC^2 + 2\cdot CD^2, \] where now is the half plus the added segment. The derivation parallels II.9 exactly with extension in place of internal cut, and the symmetry is what Heath emphasises.

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