Proposition·Untested·2605.00009

Proposition II.11

To cut a given straight line so that the rectangle contained by the whole and one of the segments is equal to the square on the remaining segment.

Proof

Let be the given straight line. Describe on the square (I.46). Bisect at (I.10) and join . Produce to in the direction of (Postulate 2), and lay off on produced so that (I.3, taking as the standard length). On describe the square (I.46); produce to meet at . Then by II.6 applied to bisected at with extension , the rectangle on , together with the square on equals the square on . But , so this rectangle plus square on equals the square on , which by I.47 (in , right-angled at ) equals the square on plus the square on . Subtracting the square on from both sides (Common Notion 3): \[ CF \cdot FA \;=\; AB^2. \] The rectangle on , (= since ) equals the square on . Subtracting the common rectangle on , from both, the square on equals the rectangle on and . Setting on (point on with ) gives the desired section: .

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