Proposition·Untested·2605.00009

Proposition II.5

If a straight line be cut into equal and unequal segments, the rectangle contained by the unequal segments of the whole together with the square on the straight line between the points of section is equal to the square on the half.

Proof

Let be bisected at (I.10) and cut unequally at . Describe on the square (I.46), join , and through draw parallel to or (I.31), meeting at and at . Through draw parallel to or (I.31), meeting at and at . Through draw parallel to or (I.31), meeting extended at . The complement equals the complement in the square (I.43). Add to each the square ; then the rectangle plus the square equals the rectangle plus the same square. But together with rectangle -equivalent piece (which equals since and the lines are parallel) fills the gnomon , plus the square on , equals the square on . Thus the rectangle together with the square on equals the square on .

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