Proof
Let and be chords with . From the centre
drop perpendiculars to and to (I.12). By III.3,
and , so . Join ,
(both radii, so equal). In right triangles
and (right angles at , ), I.47 gives and . Subtracting (Common Notion
3) and using , gives , hence . Conversely, if , the same I.47 identity gives and hence .
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Full neighborhood
Depends on (5)
- III.3Proposition III.3If in a circle a straight line through the centre bisect a straight line not through the centre, it also cuts it at…
- I.12Proposition I.12To draw a perpendicular straight line to a given infinite straight line from a given point not on it.
- I.47Proposition I.47In right-angled triangles the square on the side subtending the right angle is equal to the squares on the sides…
- 3Common notion 3If equals be subtracted from equals, the remainders are equal.
- III.4Definition III.4In a circle, straight lines are said to be equally distant from the centre when the perpendiculars drawn to them from…
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