Proof
Let be the given segment with chord and arc through .
Pick on the arc; join , . Bisect at and
at (I.10). At and erect perpendiculars to and
respectively (I.11). By III.3 / III.9 these perpendiculars
both pass through the centre, so their intersection is the
centre. With centre and radius describe the full circle.
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Full neighborhood
Depends on (5)
- III.3Proposition III.3If in a circle a straight line through the centre bisect a straight line not through the centre, it also cuts it at…
- III.9Proposition III.9If a point be taken within a circle, and more than two equal straight lines fall from the point on the circle, the…
- I.10Proposition I.10To bisect a given finite straight line.
- I.11Proposition I.11To draw a straight line at right angles to a given straight line from a given point on it.
- I.15Definition I.15A circle is a plane figure contained by one line such that all the straight lines falling upon it from one point among…
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