Proposition·Untested·2605.00009

Proposition III.31

In a circle the angle in the semicircle is right, that in a greater segment less than a right angle, and that in a less segment greater than a right angle.

Proof

Let be a diameter of the circle with centre , and any point on the circle other than , . Join , , . Since (radii), is isoceles, so by I.5, . Similarly is isoceles with . By I.32, the angles of sum to two right angles: \[ \angle OAC + \angle OBC + \angle ACB \;=\; \text{two right angles.} \] But by the isoceles equalities. Substituting, two right angles, so is right. For inscribed angles in segments greater than a semicircle, the arc is less than a semicircle, so by III.20 the inscribed angle is half a central angle less than two right angles — hence less than a right angle. The lesser-segment case is symmetric.

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