Proof
Bisect two adjacent interior angles of the pentagon (I.9); their
bisectors meet at a point . Drop perpendiculars from to each
side (I.12); by I.4 these perpendiculars are equal. The circle on
with that common radius touches every side (III.16).
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Depends on (4)
- I.4Proposition I.4If two triangles have two sides equal to two sides respectively, and have the angles contained by the equal straight…
- I.9Proposition I.9To bisect a given rectilineal angle.
- I.12Proposition I.12To draw a perpendicular straight line to a given infinite straight line from a given point not on it.
- III.16Proposition III.16The straight line drawn at right angles to the diameter of a circle from its extremity will fall outside the circle,…
Required by (dependents) (1)
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