Proposition·Untested·2605.00009

Proposition V.1

If there be any number of magnitudes whatever which are, respectively, equimultiples of any magnitudes equal in multitude, then, whatever multiple one of the magnitudes is of one, that multiple also will all be of all.

Proof

Each magnitude is a sum of copies of the corresponding base magnitude. Sum across the magnitudes; by Common Notion 2 the total is copies of the sum.

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