Proof
For with , the sequence is in continued proportion with ratio ; by
VII.27 the extremes are coprime, so by VIII.1 the sequence is least
in its ratio.
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Depends on (2)
Required by (dependents) (4)
- VIII.4Proposition VIII.4Given as many ratios as we please in least numbers, to find numbers in continued proportion which are the least in the…
- VIII.8Proposition VIII.8If between two numbers there fall numbers in continued proportion with them, then, however many numbers fall between…
- VIII.9Proposition VIII.9If two numbers be prime to one another, and numbers fall between them in continued proportion, then, however many…
- VIII.13Proposition VIII.13If there be as many numbers as we please in continued proportion, and each by multiplying itself make some number, the…
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