Proof
Neither term commensurable with the assigned rational, but the
square-discriminant commensurable with the greater (X.29 variant).
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Depends on (3)
- X.29Proposition X.29To find two rational straight lines commensurable in square only such that the square on the greater is greater than…
- X.48Proposition X.48To find the first binomial straight line.
- X.II.3Definition X.II.3If neither term is commensurable in length with the assigned rational straight line, the whole is called a third…
Required by (dependents) (3)
- X.56Proposition X.56If an area be contained by a rational straight line and the third binomial, the side of the area is the irrational…
- X.62Proposition X.62The square on the second bimedial straight line applied to a rational straight line produces as breadth the third…
- X.87Proposition X.87To find the third apotome.
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