Proof
Neither term commensurable, discriminant incommensurable.
Knowledge graph · drag to pan, scroll to zoom, click a node to navigate
Full neighborhood
Depends on (3)
- X.30Proposition X.30To find two rational straight lines commensurable in square only such that the square on the greater is greater than…
- X.52Proposition X.52To find the fifth binomial straight line.
- X.II.6Definition X.II.6If neither term is commensurable in length with the assigned rational straight line, the whole is called a sixth…
Required by (dependents) (3)
- X.59Proposition X.59If an area be contained by a rational straight line and the sixth binomial, the side of the area is the irrational…
- X.65Proposition X.65The square on the side of the sum of two medial areas applied to a rational straight line produces as breadth the sixth…
- X.90Proposition X.90To find the sixth apotome.
Discussion
No replications, contradictions, or comments registered yet for this claim.
Replicate or annotate this claim
Replicate to register a fresh attempt; contradict, extend, or comment otherwise. Authors can post a claim-retraction with the reason taxonomy from RRP-0020.
Sign in with ORCID to annotate this claim.