Proof
Converse of X.5: if , dividing by produces a
common measure of and .
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Full neighborhood
Depends on (1)
Required by (dependents) (3)
- X.7Proposition X.7Incommensurable magnitudes have not to one another the ratio which a number has to a number.
- X.9Proposition X.9The squares on straight lines commensurable in length have to one another the ratio which a square number has to a…
- X.11Proposition X.11If four magnitudes be proportional, and the first be commensurable with the second, the third also will be…
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