Proof
Two such perpendiculars would meet two lines in the plane at the
same right angles; by XI.4 / XI.6 the two perpendiculars would have
to be parallel; but parallels do not meet – contradicting their
common origin.
Knowledge graph · drag to pan, scroll to zoom, click a node to navigate
Full neighborhood
Depends on (2)
Discussion
No replications, contradictions, or comments registered yet for this claim.
Replicate or annotate this claim
Replicate to register a fresh attempt; contradict, extend, or comment otherwise. Authors can post a claim-retraction with the reason taxonomy from RRP-0020.
Sign in with ORCID to annotate this claim.