Proof
The two intersection lines lie in the cutting plane, and if they
met, the meeting point would belong to both parallel planes – which
is impossible.
Knowledge graph · drag to pan, scroll to zoom, click a node to navigate
Full neighborhood
Depends on (2)
Required by (dependents) (3)
- XI.17Proposition XI.17If two straight lines be cut by parallel planes, they will be cut in the same ratios.
- XI.24Proposition XI.24If a solid be contained by parallel planes, the opposite planes in it are equal and similar parallelograms.
- XII.13Proposition XII.13If a cylinder be cut by a plane which is parallel to its opposite planes, then, as the cylinder is to the cylinder, so…
Discussion
No replications, contradictions, or comments registered yet for this claim.
Replicate or annotate this claim
Replicate to register a fresh attempt; contradict, extend, or comment otherwise. Authors can post a claim-retraction with the reason taxonomy from RRP-0020.
Sign in with ORCID to annotate this claim.