II.13 Proposition II.13
In acute-angled triangles the square on the side subtending the acute angle is less than the squares on the sides containing the acute angle by twice the rectangle contained by one of the sides about the acute angle (namely that on which the perpendicular falls) and the straight line cut off within by the perpendicular.
Proof
Let △ABC be acute-angled, with the acute angle at B.
From C drop a perpendicular CD to AB (I.12). Since the angle
at B