To two given straight lines to find a mean proportional.
Proof
Lay the two segments end-to-end as AB, BC on a single line; on
AC as diameter describe a semicircle (Postulate 3, III.31 implicit).
Erect the perpendicular BD at B to the diameter; then △ABD, △BDC, and △ABC are similar by VI.8, so
AB:BD=BD:BC, making BD the required mean proportional.