Proof
Bisect a side by I.10; produce a median; apply I.4 to obtain a
congruent triangle that has the interior angle as one of its parts;
Common Notion 5 closes the inequality.
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Full neighborhood
Depends on (3)
Required by (dependents) (6)
- I.17Proposition I.17In any triangle two angles taken together in any manner are less than two right angles.
- I.18Proposition I.18In any triangle the greater side subtends the greater angle.
- I.21Proposition I.21If on one of the sides of a triangle, from its extremities, there be constructed two straight lines meeting within the…
- I.26Proposition I.26If two triangles have the two angles equal to two angles respectively, and one side equal to one side, namely either…
- I.27Proposition I.27If a straight line falling on two straight lines make the alternate angles equal to one another, the straight lines…
- III.2Proposition III.2If on the circumference of a circle two points be taken at random, the straight line joining the points will fall…
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