Proof
Apply I.4 to the congruent angle–side–angle case; for the AAS case
combine I.4 with I.16.
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Full neighborhood
Depends on (2)
Required by (dependents) (3)
- I.34Proposition I.34In parallelogrammic areas the opposite sides and angles are equal to one another, and the diameter bisects the areas.
- III.3Proposition III.3If in a circle a straight line through the centre bisect a straight line not through the centre, it also cuts it at…
- IV.4Proposition IV.4In a given triangle to inscribe a circle.
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